2004 AMC 8 第 3 题

先试着解答 2004 AMC 8 第 3 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2004 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

3.

十二个朋友在奥斯卡超大份牡蛎餐厅共进晚餐,每人点了一份餐。餐量非常大,足够 1818 个人吃。如果他们共享食物,为了刚好够这 1212 个人吃,他们本应点多少份餐?
Twelve friends met for dinner at Oscar’s Overstuffed Oyster House, and each ordered one meal. The portions were so large, there was enough food for 1818 people. If they shared, how many meals should they have ordered to have just enough food for the 1212 of them?
88
99
1010
1515
1818
答案:A
知识点:比与比例
小提示:
1212 份餐足够 1818 个人吃
The 1212 meals made enough food for 1818 people.
大提示:
先求每人需要多少份餐,再按 1212 个人缩放
Find how many meals are needed per person, then scale to 1212 people.
解答:
1212 份餐能喂饱 1818 个人,所以一份餐能喂饱 1812=32\dfrac{18}{12} = \dfrac{3}{2} 个人。
因此所需餐数为 12÷32=812 \div \dfrac{3}{2} = 8,正好够 1212 个人吃。
所以正确答案是 A。
Note that 1212 meals feed 1818 people. This means that one meal feeds 1812=32\dfrac{18}{12} = \dfrac{3}{2} people.
This means that they need 12÷32=812 \div \dfrac{3}{2} = 8 meals for 1212 people.
Thus, A is the correct answer.
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