Question

四个互不相同的正偶数的平均数最小可能是多少？

What is the smallest possible average of four distinct positive even integers?

$3$

$4$

$5$

$6$

$7$

要得到最小可能平均数，应选 $4$ 个最小的正偶数。

这给出 $\dfrac{2 + 4 + 6 + 8}{4} = \dfrac{20}{4}$ $= 5.$

所以正确答案是 C。

To get the smallest possible average, we want to use the smallest $4$ positive even integers.

This can be achieved as follows: $\dfrac{2 + 4 + 6 + 8}{4} = \dfrac{20}{4}$ $= 5.$

Thus, C is the correct answer.